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AM is a median of a ∆ABC.Prove that AB+BC+CA>2AM. |
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Answer» Answer: In triangle ABM AB+ BM > AM…….(1) In rriangle ACM AC + CM > AM…….(2) By ADDING the EQUATION 1 & 2 we get AB + AC +( BM+CM) > 2AM where BM +CM = BC ( acc. to FIGURE) HENCE …. AB + BC + CA > 2 AM PROVED……….. mark as brainlist |
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