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Ammoina carbonate when heated to `200^(@)C` gives a mixture of `NH_(3)` and `CO_(2)` vapour with a density of `13.0` What is the degree of dissociation of ammonium carbonate ?A. `3//2`B. `1//2`C. 2D. 1 |
Answer» Correct Answer - D `NH_(2)COONH_(4)hArr2NH_(3) + CO_(2)` `alpha =(D-d)/((n-1)d)` where D is the density (initial) `D=(mol.wt)/(2) =(78)/(2)=39` n=no. of product = 3d = final density `alpha =(39-13)/((3-13)13)=1` , so `alpha =1` |
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