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Ammonia gas at 15 atm is introduced in a rigid vessel at 300 K. At equilibrium the total pressure of the vessel is found to be 40.11 atm at `300^@C`.The degree of dissociation of `NH_3` will be :A. `0.6`B. `0.4`C. unpredictableD. None of these |
Answer» Correct Answer - B `2NH_(3)hArrN_(2) + 3H_(2)` `T = 300K` 15 atm `T = 573 K` `(15)/(300) (573)` atm `(15)/(300) (573)` `[1 + alpha) = 40.11` `implies` `alpha = 0.4` |
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