1.

An 80 muC charge is given to the 4muF capacitor in the circuit shown in Fig. so the upper plate A is positively charged. An unknown resistance R is connected in the left limb. As soon as the switch S in the central limb is closed, a current of 2 A flows through the 2Omega resistor in the central limb. The capacitive time constant for the circuit is

Answer»

`56 mus `
`8 mu s`
`200 mu s`
`40 mus `

SOLUTION :d. Potential difference across the central limb = 16 V = Potential difference across `16 Omega` = potential across the LEFT
limb.
CURRENT through `16Omega` = 1A
Current through the left limb = 1 A and R = `11 Omega`
`:. tau_(C) = (16/2+2) Omega xx (4 xx 10^(-6)) F = 40 mus` .


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