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An 8microF capacitor is connected in series with a 0.5 megaohm resistor. The DC voltage supply is 200V. Calculate the current in the capacitor 4s after the power is supplied.(a) 79 microA(b) 68 microA(c) 48 microA(d) 74 microAThis question was posed to me by my college director while I was bunking the class.My question comes from Discharge of a Capacitor Through a Resistor topic in section Capacitance and Capacitors of Basic Electrical Engineering

Answer» CORRECT choice is (d) 74 microA

Easy explanation: In the given question, the time constant is EQUAL to the time taken= 4s. Hence the value of current will be 37% of its initial value = I=0.37*200 = 74 microA.


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