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An 8microF capacitor is connected in series with a 0.5 megaohm resistor. The DC voltage supply is 200V. Calculate the voltage in the capacitor 4s after the power is supplied.(a) 123.4V(b) 126.4V(c) 124.5V(d) 132.5VI got this question in a national level competition.I'm obligated to ask this question of Discharge of a Capacitor Through a Resistor in section Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Right choice is (b) 126.4V

Explanation: We can get the VALUE of the potential difference across the capacitor in 4s, from the following equation:

VC=V(1-e^-t /RC). SUBSTITUTING the VALUES in the given equation, we get Vc = 126.4V.



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