An α-particle of energy 10 MeV is scattered through 180^o by a fixed uranium nucleus. Calculate the order of distance of the closest approach?(a) 10^-20cm(b) 10^-12cm(c) 10^-11cm(d) 10^12cmThis question was posed to me in class test.This intriguing question comes from Alpha-Particle Scattering and Rutherford’s Nuclear Model of Atom in section Atoms of Physics – Class 12

An α-particle of energy 10 MeV is scattered through 180^o by a fixed

1.	An α-particle of energy 10 MeV is scattered through 180^o by a fixed uranium nucleus. Calculate the order of distance of the closest approach?(a) 10^-20cm(b) 10^-12cm(c) 10^-11cm(d) 10^12cmThis question was posed to me in class test.This intriguing question comes from Alpha-Particle Scattering and Rutherford’s Nuclear Model of Atom in section Atoms of Physics – Class 12
Answer» Correct ANSWER is (B) 10^-12cm To ELABORATE: r0 = \(\frac {(2Ze^2)}{(4\pi \varepsilon_0 (\frac {1}{2}m v^2))}\) r0 = \(\frac {9 \times 10^9 \times 2 \times 92 \times (1.6 \times 10^{-19})^2}{10 \times 1 \times 10^{-13}}\) J r0 = 4.239 × 10^-14 m r0 = 4.2 × 10^-12 CM.

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