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An ac source is connected across a resistance of `10 Omega` The power dissipated in the resistor is `100W` The rms valuse of the current and voltge are .A. `sqrt10 A ,sqrt(1000)V`B. `2 sqrt(10) A ,2 sqrt(1000)V`C. `2 sqrt(10) A, 2sqrt(1000)V`D. `sqrt(10) A , 2sqrt(1000) V` |
Answer» Correct Answer - A `P = i^(2)_(rms) R implies 100 i^(2) _(rms) xx 10` `i_(rms) = sqrt10A` `V_(rms) = i_(rms) R =10 sqrt10 = sqrt(1000)V` . |
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