InterviewSolution
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InterviewSolution
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An ac source is connected to two circuits as shown Obtain current through resistance R at resonance in both the circuits . |
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Answer» Solution :In sericse resonance impedance is minimum `(as X_(L) = X_(C))` and equal to resistance `Z =R` `I = (V)/(Z) = (V)/( R)` `L` and `C` are in parallel `i_(1) = (V)/(X_(L)` lags voltage by `pi//2` `i_(2) = (V)/(X_(C))` leads voltage by `pi//2` `i = i_(2) -i_(1) = (V)/(X_(C) - (V)/(X_(L))` `(V)/(Z) = (V')/(X_(C)) - (1)/(X_(L))` At resonance, `X_(C) = X_(L)` `(1)/(Z) = 0 implies Z =oo` Impedance of overall circuit `Z =R + oo = oo` CURRENT through resistance `=0`   .
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