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An ac source is of `(200)/(sqrt(2))` V, 50 Hz. The value of voltage after `(1)/(600)s` from the start isA. 200 VB. `(200)/(sqrt(2))V`C. 100 VD. 50 V

Answer» Correct Answer - C
`V_("rms")=(200)/(sqrt(2))V`
`V_(0)=sqrt(2)xx(200)/(sqrt(2))=200 V`
`V=V_(0)sin 2pi upsilon t=200 sin (2pixx50xx(1)/(600))`
`=200 "sin"(pi)/(6)=200xx(1)/(2)=100 V`


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