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An ac source is of `(200)/(sqrt(2))` V, 50 Hz. The value of voltage after `(1)/(600)s` from the start isA. 200 VB. `(200)/(sqrt(2))V`C. 100 VD. 50 V |
Answer» Correct Answer - C `V_("rms")=(200)/(sqrt(2))V` `V_(0)=sqrt(2)xx(200)/(sqrt(2))=200 V` `V=V_(0)sin 2pi upsilon t=200 sin (2pixx50xx(1)/(600))` `=200 "sin"(pi)/(6)=200xx(1)/(2)=100 V` |
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