An AC source producing `emf` `epsilon = epsilon_0 [cos(100 pi s^(-1)) t + cos (500 pi s^(-1))t]` is connected in series with a capacitor and a resistor. The steady-state current in the circuit is found to be `I = i_1 cos [(100 pi s^(-1) t + varphi_1] + i_2 cos [(500 pi s^(-1))t +phi_2]`.A. `i_(1) ge i_(2)`B. `i_(1) = i_(2)`C. `i_(1) le i_(2)`D. the information is insufficient to find the relation between `i_(1)` and `i_(2)`.

An AC source producing `emf` `epsilon = epsilon_0 [cos(100 pi s^(-1))

1.	An AC source producing `emf` `epsilon = epsilon_0 [cos(100 pi s^(-1)) t + cos (500 pi s^(-1))t]` is connected in series with a capacitor and a resistor. The steady-state current in the circuit is found to be `I = i_1 cos [(100 pi s^(-1) t + varphi_1] + i_2 cos [(500 pi s^(-1))t +phi_2]`.A. `i_(1) ge i_(2)`B. `i_(1) = i_(2)`C. `i_(1) le i_(2)`D. the information is insufficient to find the relation between `i_(1)` and `i_(2)`.
Answer» Correct Answer - C `i_(1) = (in_(0))/(sqrt(R^(2) + ((1)/(100 pi C))^(2))) , i_(2) = (in_(0))/(sqrt(R^(2) + ((1)/(500 pi C))^(2)))` Clearly `i_(1) lt i_(2)`

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