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An AC source producing `emf` `epsilon = epsilon_0 [cos(100 pi s^(-1)) t + cos (500 pi s^(-1))t]` is connected in series with a capacitor and a resistor. The steady-state current in the circuit is found to be `I = i_1 cos [(100 pi s^(-1) t + varphi_1] + i_2 cos [(500 pi s^(-1))t +phi_2]`.A. `I_(1) gt i_(2)`B. `i_(1) =i_(2)`C. `i_(1) lt i_(2)`D. the information is insufficient to find the relation between is found to be

Answer» Correct Answer - C
`"Impedence z is give by z "sqrt(((1)/(omegaC))^(2)+R^(2))`
For higher `omega`, z will be lower so current will be higher


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