1.

An `AC` voltage is applied acrss a series combination of `L` and `R`. If the voltage drop across the resistor and inductor are `20 V` and `15 V` respectiely, then applied peak voltage isA. `25V`B. `35V`C. `25sqrt2V`D. `5sqrt7V`

Answer» Correct Answer - C
`V=sqrt(V_R^2+V_L^2)`
`=sqrt((20)^2(15)^2)=25V`
But this is the rms value.
`:.` Peak value of `=sqrt2 V_("rms")=25sqrt(2)V`.


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