1.

An AC voltage V = 5 cos (1000 t) V is applied to a L-R series circuit of inductance 3 mH and resistance 4Omega . The value of maximum current in the circuit is …….. A.

Answer»

1
`5/sqrt7`
`5/7`
0.8

Solution :By comparing ,
V=5 cos (100T)V with `V=V_m cos (omegat)V`
`omega`=1000 rad/s , `V_m` = 5 V
Impedence of SERIES connectionof L-R,
`|Z|=sqrt((omegaL)^2 + R^2)`
`=sqrt((1000xx3xx10^(-3))^2+(4)^2)`
`=sqrt(9+16)`
`=sqrt25`
`= 5Omega`
`THEREFORE I_m=V_m/"|Z|"=5/5` = 1 A


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