An acid catalysed hydrolysis of ester follows rate law,R=k[CH_3COOC_2H_5][H^+].Half life in presence of 0.1M HA (ka=10^(-5)) is 100 min. Then half life (in min) in presence of 0.01M HCl.

An acid catalysed hydrolysis of ester follows rate law,R=k[CH_3COOC_2H

1.	An acid catalysed hydrolysis of ester follows rate law,R=k[CH_3COOC_2H_5][H^+].Half life in presence of 0.1M HA (ka=10^(-5)) is 100 min. Then half life (in min) in presence of 0.01M HCl.
Answer» SOLUTION :`k^(-1)=k[H^+]` `H^+=sqrt(0.1xx10^(-5))=10^(-3)` `100="In2"/(kxx10^(-3))` `t_(1//2)="In2"/(kxx10^(-2))`=10 MIN

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An acid catalysed hydrolysis of ester follows rate law,R=k[CH_3COOC_2H_5][H^+].Half life in presence of 0.1M HA (ka=10^(-5)​) is 100 min. Then half life (in min) in presence of 0.01M HCl.

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An acid catalysed hydrolysis of ester follows rate law,R=k[CH_3COOC_2H_5][H^+].Half life in presence of 0.1M HA (ka=10^(-5)) is 100 min. Then half life (in min) in presence of 0.01M HCl.