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An adult weighing 600 N raises the centre of gravity of his body by 0.25 m while taking each step of 1 m length in jogging. If he jogs for 6 km, the energy utilised by him in jogging isA. `9xx10^6` JB. `9xx10^5` JC. `6xx10^6` JD. `6xx10^5` J |
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Answer» Correct Answer - B Here, mg = 600 N, h = 0.25 m Length of each step = 1 m `therefore` No of steps in 6 km is `N=(6xx10^3m)/(1 m) =6000` `therefore` Energy utilised in jogging is `E=Nmgh = 6000 xx 600 N xx 0.25 m = 9 xx 10^(5)J` |
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