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An aeroplane is flying at a height of 2000 m above the ground horizontally with a uniform speed of 720 km/h. At what angle of sight (w.r. to the horizontal) should the pilot drop a bomb so as to hit target on the ground ? |
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Answer» 26°.57 `200ms^(-1)` Height h = 2000 m Now LET X be the horizontal distance, then `h=0+1/2g t^(2)` or, `2000=1/2xx10t^(2)` `t=20sec` x = ut = `200 xx 20` `=1/2` or `theta=tan^(-1)0.5=26^@57.` |
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