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An aeroplane is flying horizontally with a velocity of216 km/hr and at a height of 1960 m. When it isvertically above a point A on the ground, a bomb isreleased from it. The bomb strikes the ground at pointB. The distance AB is (ignoring air resistance)29.(1) 1200 m(2) 0.33 m(3) 3.33 km(4) 33 km |
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Answer» When the bomb is dropped, it will have an initial horizontal velocity which is equal to the speed of the aeroplane. So the bomb fall and travel forward too.initial horizontal velocity, = 216 km/h=216×5/18=60 m/sinitial vertical velocity, = 0height, h = 1960mtime taken to fall = th=ut+1/2×gt^2........................g=9.8 1960=4.9t^2 t=√400=20sec so, AB=ux×t=60×20=1200m |
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