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An aeroplane moving in a circular path with a speed `250 km//h`. The change in velocity in half of the revolution is.A. 500 km/hrB. 250 km/hrC. 125 km/hrD. zero |
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Answer» Correct Answer - A `v_(i) = 250km//hr` `v_(r) = 2 sin .(theta)/(2)` `theta= pi` Then `v_(F) = 2 xx 250 xx sin .(pi)/(2)km//hr` `" "v_(F) = 500 km//hr` |
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