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An air capacitor is charged upto a potential `V_1`. It is connected in parallel to an identical uncharged capacitor filled with a dielectric medium. After redistribution of charge if the potential difference of this combination is V, then the dielectric constant of the substance will beA. `V^(2)(V_(1)-V)`B. `V(V_(1)-V)`C. `V/((V_(1)-V))`D. `((V_(1)-V))/V` |
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Answer» Correct Answer - D `V=(CV_(1))/(C+KC)rArr K=(V_(1)-V)/V` |
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