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An air columbn in pipe, which is closed at one end, will be in resonance with a vibrating tuning fork of frequency `264 Hz` if the length of the column in `cm` is :A. (a) `31.25`B. ( b) `62.50`C. ( c ) `93.75`D. (d) `125` |
Answer» Correct Answer - A::C (a,c) The wavelength possible in an air column in a pipe which has one closed end is `lambda = (4l)/((2n + 1))` So, `c = vlambda` `300 = 264 xx (4l)/(2n + 1)` `v = 264 Hz` as it is in resonnance with a vibrating tuning fork of frequency `264 Hz`. `l = (330 xx (2n +1))/(264 xx 4)` For `n = 1`, `l = 0.3125m = 31.25cm` For `n = 2`, `l = 0.9375m = 93.75cm` |
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