1.

An alpha-nucleus of energy (1)/(2)mv^(2) bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the O-nucleus will be proportional to ......

Answer»

`(Ze)^(-1)`
`v^(2)`
`m^(-1)`
`v^(-1)`

Solution :DISTANCE of closest approach to `r_(0)=(Ze^(2))/(4piin_(0)xx(1)/(2)mv^(2))`
`:.r_(0)PROP(1)/(m)` [All other terms are CONSTANT]


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