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An alpha-particle accelerated through `V` volt is fired towards a nucleus . Its distance of closest approach is . `r` If a protons is accelerated through the same potential and fired towards the same nucleus , the distance of closest approach of proton will be .A. `r`B. `2r`C. `r/2`D. `r/4` |
Answer» Correct Answer - A `K.E=PERightarrowq_(1)V=1/(4piepsilon_(0))(q_(1)q_(2))/r` independent of charge of the particle projected |
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