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An alpha- particle and a proton are accelerated through same potential difference. Find the ratio. (v_(alpha)//v_(p)) of velocities acquired by two particles. |
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Answer» <P> Solution :If a PARTICLE of mass m and charge q on accelerating through a potential difference V ACQUIRES a velocity v then `(1)/(2)mv^(2)=qV or v=sqrt((2qV)/(m))``rArr""(v_(alpha))/(v_(p))=sqrt((a_(alpha))/(q_(p))xx(m_(p))/(m_(alpha)))"[SINCE V = constant]"` `rArr""(v_(alpha))/(v_(p))=sqrt(2XX(1)/(4))=sqrt((1)/(2)) or v_(alpha):v_(p)=1:sqrt2`. |
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