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An alpha -particle and a proton are fired through the same magnetic fields which is perpendicular to their velocity vectors. The alpha-particle and the proton move such that radius of curvature of their path is same. Find the ratio of their de Broglie wavelengths. |
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Answer» <P> Solution :SINCE, `Bqv=(mv^(2))/(R)ormv=QBR`The de Broglie WAVELENGTH `lamda=(h)/(mv)=(h)/(qBr)` `(lamda_(alpha-"particle"))/(lamda_("proton"))=(q_(p)r_(p))/(q_(alpha)r_(alpha))=(1)/(2)(1//2)=(1)/(2)` |
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