1.

An alpha particle is accelerated through a potential difference of 100 volts. Its kinetic energy will be

Answer»

1 MeV
2 MeV
4 MeV
8 MeV

Solution :KINETIC ENERGY `K = QV = (+ 2E)xx (10^6V) = 2 xx 10^6 eV= 2MeV`


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