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An alpha particle of energy 4MeV is scattered through an angle of `180^(@)` by a gold foil (Z=79). Calculate the maximum volume in which positive charge of the atom is likely to be concetrated? |
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Answer» Correct Answer - `7.7xx20^(-40)m^(3)` Maximum volume in which positive charge of atom is likely to be concentrated is `V_(0)=4/3pir_(0)^(3)` Calculate `r_(0)` form the usual formula. |
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