An alpha particle of energy 5 MeV is scattered through 180^(@) by a found uramiam nucleus . The distance of closest approach is of the order of

An alpha particle of energy 5 MeV is scattered through 180^(@) by a fo

1.	An alpha particle of energy 5 MeV is scattered through 180^(@) by a found uramiam nucleus . The distance of closest approach is of the order of
Answer» `5.3 xx 10^(-12) m` `5.3 xx 10^(-13) m` `5.3 xx 10^(-14) m` `5.3 xx 10^(-15) m` Answer :C

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An alpha particle of energy 5 MeV is scattered through 180^(@) by a found uramiam nucleus . The distance of closest approach is of the order of

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