1.

An alpha particle of mass m moves on a circular path of radius r in a plane inside and normal to uniform magnetic field B. The time taken by this particle to complete one revolution is ________

Answer»

`(4pieB)/m`
`(8PIE^(2)B)/m`
`(4pime)/B`
`(pim)/(Be)`

Solution :When `alpha`-particle of charge q = 2e enters perpendicularly to MAGNETIC field, magnetic force provides the centripetal force.
`(MV^(2))/r=Bqv`
`(mv)/r=Bq`
`(mxromega)/r=B(2e)`
`(2pi)/T=(2Be)/m""thereforeT=(2pim)/(2Be)=(pim)/(Be)`


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