1.

An alpha particle of velocity 1.6xx10^(7) ms^(-1) approaches a gold nucleus (Z=79). Calculate the distance of the closestapproach. Mass of an alpha particle is 6.6xx10^(-27) kg. What is the significance of this closest approach?

Answer»


ANSWER :`4.3 XX 10^(-14)m` , the size of the nucleus cannot be GREATER than `4.3 xx 10^(-14)m`.


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