1.

An alternating current by frequency v is flowing in a circuit containing a resistance R and inductance L in series. The impedance of this circuit is

Answer»

R = `2PI vL`
`sqrt(R^(2) + 4PI^(2) v^(2)L^(2))`
`sqrt(R^(2) + L^(2))`
`sqrt(R^(2) + 2pi vL)`

SOLUTION :Peak value of EMF `=sqrt(2) V_(rms) = sqrt(2) xx 220 = 311 V`


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