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An alternating current having peak value `14 A` is used to heat a metal wire. To produce the same heating effect, a constant current `i` can be used where `i` isA. `14A`B. about `20A`C. `7A`D. about `10A` |
Answer» Correct Answer - D `I = I _(0)/(sqrt2) = (14)/(1.4) =10 A` |
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