Saved Bookmarks
| 1. |
An alternating current is flowing through a series LCR circuit. It is found that the current reaches a value of 1 mA at both 200 Hz and 800 Hz frequency. What is the resonance frequency of the circuit ? |
|
Answer» 600 Hz For maximum value of current `omega L-(1)/(omega C)=0`or`omega L=(1)/(omega C) ""`…..(i) Resonance frequency of series LCR ciruit is `omega = (1)/(sqrt(LC))` From (i),`200 L=(1)/(800 C) ""` [`because` current reaches a value of 1 mA] or `(1)/(LC)=200xx800` or `(1)/(sqrt(LC))=sqrt(200xx800)=400 Hz` |
|