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An alternating current of rms value 10 A is passed through a 12 Omega resistor. The maximum potential difference across the resistor is |
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Answer» 20 V The maximum current is `I_(m)=sqrt(2)I_(rms)=sqrt(2)(10)=10sqrt(2)A` Maximum POTENTIAL DIFFERENCE is `V_(m)=I_(m)R` `=10 sqrt(2)xx12 =169.68` V. |
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