1.

An alternating emf given by equation `e=300sin(100pi)t V` is applied to a resistance `100 Omega`. The rms current through the circuit is (in amperes).A. `3/sqrt(2)`B. `9/sqrt(2)`C. 3D. `6/sqrt(2)`

Answer» Correct Answer - A
The given equation, e=`300 sin (100pi)t]`..............(i)
We know that, `e=e_(0)sinomegat`............(ii)
On comparing Eqs (i) and (ii), we get
`e_(0)` = 300 V and `R= 100Omega`
The rms current through the circuit `I_(rms) =?`
`I_(rms) = e_(0)/sqrt(2R) = 300/(sqrt(2) xx 100) = 3/sqrt(2)` A


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