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An alternating supply of 220 V is applied across a circuit with resistance `22 Omega` and impedance `44 Omega`. The power dissipated in the circuit isA. 1100 WB. 550 WC. 2200 WD. (2200/3) W |
Answer» Correct Answer - B Here, V = 220 V Resistance, `R = 22 Omega` Impedance, `Z = 44 Omega` Current in circuit, `I=(V)/(Z)=(220V)/(44 Omega)=5 A` Power dissipated in the circuit, `P = I^(2)R=(5)^(2)xx22=550 W` |
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