An alternating voltage `E=200sqrt(2) sin (100 t)V` is connected to a `1 muF` capacitor through an ac ammeter (it reads rms value). What will be the reading of he ammeter?

An alternating voltage `E=200sqrt(2) sin (100 t)V` is connected to a `

1.	An alternating voltage `E=200sqrt(2) sin (100 t)V` is connected to a `1 muF` capacitor through an ac ammeter (it reads rms value). What will be the reading of he ammeter?
Answer» Comparing `E = 200 sqrt(2) sin (100 t)` with `E = E_(0) sin omega t, E_(0) = 200 sqrt(2) V` and `omega = 100 ("rad"//s)` `X_(C ) = (1)/(oemga C) = (1)/(100 xx 10^(-6)) = 10^(4) Omega` `I_("rms") = (E_("rms"))/(Z) = (E_(0))/(sqrt(2)X_(C )) = (200 sqrt(2))/(sqrt(2) xx 10^(4)) = 20 mA`

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An alternating voltage `E=200sqrt(2) sin (100 t)V` is connected to a `1 muF` capacitor through an ac ammeter (it reads rms value). What will be the reading of he ammeter?

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