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An alternating voltage given as V=200sqrt2sin (100t)V is applied to a capacitor of 1 muf. The current reading of the ammeter will be equal to ...... mA. |
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Answer» 100 but `|Z|=1/(omegaC)=1/(100xx10^(-6))=1/10^(-4)` Now `I_(RMS)=I_m/sqrt2 =V_m/(sqrt2|Z|)=(200sqrt2)/(sqrt2xx1/(10^(-4)))` `=200xx10^(-4) =20xx10^(-3)` Amp = 20 mA |
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