1.

An alternating voltage given as V=200sqrt2sin (100t)V is applied to a capacitor of 1 muf. The current reading of the ammeter will be equal to ...... mA.

Answer»

100
20
40
80

Solution :`I_m=V_m/"|Z|"`
but `|Z|=1/(omegaC)=1/(100xx10^(-6))=1/10^(-4)`
Now `I_(RMS)=I_m/sqrt2 =V_m/(sqrt2|Z|)=(200sqrt2)/(sqrt2xx1/(10^(-4)))`
`=200xx10^(-4) =20xx10^(-3)` Amp = 20 mA


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