1.

An alternating voltage is connected in series with a resistor R and an inductor L. If the potential drop across the resistor is 200 V and across the inductor is 150 V, then what is the applied voltage ?

Answer»

350 V
250 V
500 V
300 V

Solution :`V^2=V_R^2 +V_L^2`
`THEREFORE V=sqrt(V_R^2 +V_L^2)`
`=sqrt((200)^2 + (150)^2)`
`=sqrt(40000+22500)`
`=sqrt62500`
`therefore` V=250 V


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