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An alternating voltage V = 400 sin (500omegat)V is connected to a 0.2 kOmegaresistor, what will be the rms value of current ? |
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Answer» 14.14 A `V_m`=400 V `therefore V_"RMS"=V_m/sqrt2` `I_"rms"=V_"rms"/R=V_m /(sqrt2R)=400/(sqrt2xx200)` `=2/sqrt2=sqrt2`=1.414 A |
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