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An alternating voltage V = V_0 sinomegat is applied across a circuit. As a result the current I=I_0 sin (omegat-pi/2) flows in it. The power consumed in the circuit per cycle is ……

Answer»

0
0.5 `V_0I_0`
0.707 `V_0I_0`
1.919 `V_0I_0`

Solution :Here, `V_m=V_0`
`THEREFORE I_m=I_0` and `delta=pi/2`
`therefore P=(V_0I_0)/2 "COS" delta=(V_0I_0)/2 "cos" pi/2`
`therefore` P=0 `[because "cos" pi/2 = 0]`


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