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An AM signal is represented by x(t) = (30 + 2Sin(700πt)) Cos(2πt x 10^2t)V. What is its sideband power?(a) 4W(b) 1W(c) 3W(d) 2WThis question was posed to me at a job interview.This is a very interesting question from Power Relations in AM Waves in division Amplitude Modulation of Analog Communications

Answer»

The correct choice is (B) 1W

The explanation is: Sideband power i = (m^2* PC)/2 = (PT – Pc) i.e. 451 – 450 = 1W.



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