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An AM signal is represented by x(t) = (30 + 2Sin(700πt)) Cos(2πt x 10^2t)V. Find the total power of amplitude modulated wave?(a) 453W(b) 675W(c) 789W(d) 451WI have been asked this question during an interview.I would like to ask this question from Power Relations in AM Waves topic in chapter Amplitude Modulation of Analog Communications

Answer» RIGHT answer is (d) 451W

For EXPLANATION: PT = Pc (1 + b^m^2⁄2) * pc

So, here, m = 0.066, Pc = 450W

Pt = (1+(0.0662/2))*450 = 451W.


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