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An ammeter of resistance 0.80 Omega can measure current upto 1.0 A. (i)What must be the value of shunt resistance to enable the ammeter to measure current upto 5.0 A ? (ii) What is the combined resistance of the ammeter and the shunt ? |
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Answer» Solution :(i) Shunt, `S=(R_(A)i_(G))/(i-i_(g))` `=(0.8xx1.0)/(5.0-1.0)` `=0.2 Omega` (II) Combined resistanceof ammeter and shunt `(1)/(R_("total"))=(1)/(R_(A))+(1)/(S)` `=(1)/(0.8)+(1)/(0.2)` `R_("total")=(0.8)/(5)` `rArr R_("total")=0.16 Omega` |
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