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An ammeter of resistance 0.80 Omega can measure current upto 1.0 A. What must be the value of shunt resistance to enable the ammeter to measure current upto 5.0 A ? What is the combined resistance of the ammeter and the shunt? |
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Answer» SOLUTION :Here `I_g = 1.0 A, I = 5.0 A and R_G = 0.80 Omega` `:.` RESISTANCE of shunt `r_(s) = (I_(g) cdot R_G)/(I - I_g) = (1.0 xx 0.80)/(5.0 - 1.0) = 0.20 Omega` Net resistance of the AMMETER and the shunt `R = (R_G xx r_s)/(R_G xx r_s) = (0.80 xx 0.20)/(0.80 + 0.20) = 0.16 Omega`. |
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