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An amount of solid `NGH_(4)HS` is placed ina flask already containg ammonia gas at a certain temperaturee and 0.50 atm. Pressue. Ammounium hydrogen sulphide decomposes to yield `H_(3)and H_(2)S` gases in the flask. When the decomposition reaction reaches equlibrium, the total pressure in the flask rises to `0.84` atm. The equilibrium constant for `NH_(4)HS` decompositions at this temperaturee isA. `0.30`B. `0.18`C. `0.17`D. `1.11` |
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Answer» Correct Answer - D `{:(NH_(4)HShArrNH_(3(g))+H_(2)S_((g))),(" ""a ""0.5atm"),(""a-x " "0.5+x " "x):}` Total pressure `=0.5+2x=0.84 i.e., x=0.17` `K_(p)=P_(NH_(3)).P_(H_(2)S)=(0.67).(0.17)=0.1139` |
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