InterviewSolution
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InterviewSolution
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An angular magnification (magnifying power ) of 30x is desired using on objective of focal length 1.25 cm and an eyepiece of focal length 5cm. How will you set up the compound microscope ? |
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Answer» Solution :`m_(0) = (v_(0))/(-u_(0)) , m_(e) = 1 + (D)/(f_(e)) , m = m_(o) m_(e)` `m_(e) = 1 + (25)/(5) = 6 , m = 30"" m_(0) = (m)/(m_(e)) = (30)/(6) = 5 ` ` m_(0) = (v_(0))/(-u_(0)) "i.e," 5 = (v_(0))/(-u_(0)) , v_(0) = - 5u_(0), f_(0) = 1.25 cm "" therefore (1)/(v_(0)) - (1)/(u_(0)) = (1)/(f_(0))` `(1)/(-5u_(0)) - (1)/(u_(0)) = (1)/(1.25)` Sovling `rArr u_(0) = - 1.5 cm and v_(0) = + 7.5 cm` Then `(1)/(v_(e)) - (1)/(u_(e)) = (1)/(u_(e)) = (1)/(f_(e)) , (1)/(-25) - (1)/(u_(e)) = (1)/(5) ` `- (1)/(u_(e)) = (1)/(5) + (1)/(25) = (6)/(25) "" therefore u_(e)= (-25)/(6) = - 4.2 ` cm DISTANCE between objective and eyepiece = `v_(0) + |u_(e) |= 7.5 + 4.2 = 11.7 ` cm POSITION of the OBJECT from objective = `|u_(0)| = 1.5 ` cm |
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