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An another point charge q, thrown towards the stationary point charge Q at speed v, it returns at a distance r from Q. If 2v speed is given instead of v then distance of closest approach will be ……… |
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Answer» r `:.r_(0)prop(1)/(K_(0))` where `K_(0)` is initial KINETIC energy Now `K_(0)=(1)/(2)mv_(0)^(2)` `:.K_(0)prop(1)/(v_(0)^(2))` `:.r_(0)prop(1)/(v_(0)^(2))` `:.((r_(0))_(2))/((r_(0))_(1))=((v_(01))/(v_(02)))^(2)=(v^(2))/((2V)^(2))=(1)/(4)` `:.(r_(0))_(2)=(r)/(2)""[:.(r_(0))_(1)=r]` |
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