InterviewSolution
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InterviewSolution
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An antifreeze solution is prepared from `222.6 g` of ethylene glycol `[C_(2)H_(4)(OH)_(2)]` and `200 g` of water. Calculate the molality of the solution. If the density of the solution is `1.072g mL^(-1)` then what shall be the molarity of the solution?A. `9.10,17.95`B. `10.90,16.6`C. `12.04,17.95`D. `18.2,16.97` |
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Answer» Correct Answer - A `"Molality"=("moles of solute (glycol)")/("kg of solvent")=(222.6)/(62)/0.200` `=17.95" mol "kg^(-1)` `"Total mass of solution"=222.6+200=422.6g` `"Volume of solution"=("mass")/("density")=(422.6)/(1.072)mL=(0.4226)/(1.072)L` `:."Molarity"=("moles of solute")/("litre")=(22.6//62)/(0.4226//11.072)=9.10M` |
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