1.

An arbitrary surface encloses a dipole. What is the electric flux through this surface ?

Answer»

Solution :According to Gauss.s law, the FLUX ASSOCIATED with close surface is `phi =(sumq)/epsilon_(0)` where Q is charge enclosed by closed surface.
NET charge on dipole `=-q + q=0`
`therefore` Flux associated with closed surface enclosing dipole, `phi = (-q+q)/epsilon_(0)=0`


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